Y-(2y-1)=3(y-2)

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Solution for Y-(2y-1)=3(y-2) equation: 



-(2Y-1)=3(Y-2)

We move all terms to the left:

-(2Y-1)-(3(Y-2))=0

We get rid of parentheses

-2Y-(3(Y-2))+1=0



We calculate terms in parentheses: -(3(Y-2)), so:

3(Y-2)

We multiply parentheses

3Y-6

Back to the equation:

-(3Y-6)



We get rid of parentheses

-2Y-3Y+6+1=0

We add all the numbers together, and all the variables

-5Y+7=0

We move all terms containing Y to the left, all other terms to the right

-5Y=-7

Y=-7/-5

Y=1+2/5

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