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+8=-3/5(Y-5)
We move all terms to the left:
+8-(-3/5(Y-5))=0
Domain of the equation: 5(Y-5))!=0We multiply all the terms by the denominator
Y∈R
-(-3+8*5(Y-5))=0
We calculate terms in parentheses: -(-3+8*5(Y-5)), so:
-3+8*5(Y-5)
determiningTheFunctionDomain 8*5(Y-5)-3
Wy multiply elements
40Y(Y-3
Back to the equation:
-(40Y(Y-3)
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| 0=(6x-19-10x-74)*3 | | 8n=90 | | X+34+2x+2=120 | | 9+j/15=8 | | 0=6x-19-10x-74*3 | | X+34+2x+2=150 | | 0=6x-19-10x-74 | | 2y-8+6y=8 | | -11y-8+3=24 | | 3136(t)=-16t^2+3136 | | (x+3)/5=-13 | | 85=-6-7d | | 41+x=40. | | 3x+7x-4-6=4x+56 | | 17-4z+2z=2z | | 41+x=50 | | 4−7x/2=3x+8 | | 3x-2/2x-3=3x-8/x+4 | | 6+f/16=7 | | 9+2r=10 | | 5d-7-8d=-19 | | x/3+x/7=60 | | 18(20x-13)=8x+22 | | 7j=-14 | | -5i=-10 | | 2x-7/7=9x-2/2 | | -33f=39 | | 3x-5x-5=15+x | | 3(6x+20)=2x-11 | | 3x+20°=180 | | 17=3-r | | -126a=-21 |