Y+5=1/3(x+1)

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Solution for Y+5=1/3(x+1) equation:



+5=1/3(Y+1)
We move all terms to the left:
+5-(1/3(Y+1))=0
Domain of the equation: 3(Y+1))!=0
Y∈R
We multiply all the terms by the denominator
-(1+5*3(Y+1))=0
We calculate terms in parentheses: -(1+5*3(Y+1)), so:
1+5*3(Y+1)
determiningTheFunctionDomain 5*3(Y+1)+1
Wy multiply elements
15Y(Y+1
Back to the equation:
-(15Y(Y+1)
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
15Y(Y+1
We calculate terms in parentheses: -(15Y(Y+1), so:
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We calculate terms in parentheses: -(15Y(Y+1), so:
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We calculate terms in parentheses: -(15Y(Y+1), so:
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