Y+5=1/2(x-3)

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Solution for Y+5=1/2(x-3) equation:



+5=1/2(Y-3)
We move all terms to the left:
+5-(1/2(Y-3))=0
Domain of the equation: 2(Y-3))!=0
Y∈R
We multiply all the terms by the denominator
-(1+5*2(Y-3))=0
We calculate terms in parentheses: -(1+5*2(Y-3)), so:
1+5*2(Y-3)
determiningTheFunctionDomain 5*2(Y-3)+1
Wy multiply elements
10Y(Y+1
Back to the equation:
-(10Y(Y+1)
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
10Y(Y+1
We calculate terms in parentheses: -(10Y(Y+1), so:
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We calculate terms in parentheses: -(10Y(Y+1), so:
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We calculate terms in parentheses: -(10Y(Y+1), so:
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