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+4=3/2(Y-2)
We move all terms to the left:
+4-(3/2(Y-2))=0
Domain of the equation: 2(Y-2))!=0We multiply all the terms by the denominator
Y∈R
-(3+4*2(Y-2))=0
We calculate terms in parentheses: -(3+4*2(Y-2)), so:
3+4*2(Y-2)
determiningTheFunctionDomain 4*2(Y-2)+3
Wy multiply elements
8Y(Y+3
Back to the equation:
-(8Y(Y+3)
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| 4x+5=-5(x+8) | | -3x-30=-15 | | 10/30=8/x+1 | | −243=−9(10+y) | | 4x+6=5x+30 | | (3x+22)=(x+30) | | 0.5(x+16)=3+.25(x-4) | | -4x-22=2(3x-4)+6 | | 55+(2x+18)+(4x+11)=180 | | 4/f+2=1 | | y=30-300 | | F(t)=t3+4t | | 35+x/4=19 | | a02476+5=10 | | 15x+10=16×+4 | | 8=-x+2-5x | | -3x^2+1=151 | | 5(x-5)=-6x+30 | | 306=17r | | (4x=9x-3) | | 42=52-y | | |2x-7|=|4x| | | 50+4.75=2.50x | | 2x-12(-6)=0 | | 10.8=3c | | -18-6k=9(1+3k) | | -2-2a=6(3a+3) | | -7x+12=-4(x-6) | | (4x=9x-3)/2 | | 4(t+4)=5(t+2) | | 47+74+x=180 | | 6b+5=(-25) |