Y+4(y-2)=7-5(2y-3)

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Solution for Y+4(y-2)=7-5(2y-3) equation: 



+4(Y-2)=7-5(2Y-3)

We move all terms to the left:

+4(Y-2)-(7-5(2Y-3))=0

We multiply parentheses

4Y-(7-5(2Y-3))-8=0



We calculate terms in parentheses: -(7-5(2Y-3)), so:

7-5(2Y-3)

determiningTheFunctionDomain
-5(2Y-3)+7

We multiply parentheses

-10Y+15+7

We add all the numbers together, and all the variables

-10Y+22

Back to the equation:

-(-10Y+22)



We get rid of parentheses

4Y+10Y-22-8=0

We add all the numbers together, and all the variables

14Y-30=0

We move all terms containing Y to the left, all other terms to the right

14Y=30

Y=30/14

Y=2+1/7

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