Y+4(y-2)=7-5(2y+3)

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Solution for Y+4(y-2)=7-5(2y+3) equation: 



+4(Y-2)=7-5(2Y+3)

We move all terms to the left:

+4(Y-2)-(7-5(2Y+3))=0

We multiply parentheses

4Y-(7-5(2Y+3))-8=0



We calculate terms in parentheses: -(7-5(2Y+3)), so:

7-5(2Y+3)

determiningTheFunctionDomain
-5(2Y+3)+7

We multiply parentheses

-10Y-15+7

We add all the numbers together, and all the variables

-10Y-8

Back to the equation:

-(-10Y-8)



We get rid of parentheses

4Y+10Y+8-8=0

We add all the numbers together, and all the variables

14Y=0

Y=0/14

Y=0

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