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+3=5/2(Y+2)
We move all terms to the left:
+3-(5/2(Y+2))=0
Domain of the equation: 2(Y+2))!=0We multiply all the terms by the denominator
Y∈R
-(5+3*2(Y+2))=0
We calculate terms in parentheses: -(5+3*2(Y+2)), so:
5+3*2(Y+2)
determiningTheFunctionDomain 3*2(Y+2)+5
Wy multiply elements
6Y(Y+5
Back to the equation:
-(6Y(Y+5)
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| 2w-3=35 | | 3x+6+4x-20=180 | | 2+(x+1)=17 | | 10x-1+3x+12=180 | | 400=-4x^2+100x-180 | | -8/9y=16 | | (w+18)+93+(2w+18)=180 | | (x+6)+(x+9)+(x+3)=(2x+4)+(2x+1) | | Y^2=s | | 2n*8=64 | | 10=-3m-2 | | (x=6)+(x+9)+(x+3)=(2x+4)+(2x+1) | | 33+104+x=180 | | w-3.31=8.7 | | x/11+17=8 | | (7a+a)/4=3 | | 5x+-19=-14x-9 | | (13x-8x)*9=90 | | -46=10-8x | | X+2x+3x-60+60=360 | | 17x+0=-12x+19 | | -6w/7=-18 | | (3x+48)+(4x-20)=180 | | 97-3x+69+5x=180 | | 4a=22+2a | | 15-3d=2d | | 16-3d=2d | | x^2-9x-20=-2x-2 | | x+18-5=-2 | | x^2+6x-49=6x | | 2/3=v+5 | | f(14)=20 |