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+3=2/3(Y-5)
We move all terms to the left:
+3-(2/3(Y-5))=0
Domain of the equation: 3(Y-5))!=0We multiply all the terms by the denominator
Y∈R
-(2+3*3(Y-5))=0
We calculate terms in parentheses: -(2+3*3(Y-5)), so:
2+3*3(Y-5)
determiningTheFunctionDomain 3*3(Y-5)+2
Wy multiply elements
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Back to the equation:
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| 51=4x+1 | | (19x-2)+(7x=-35) | | (8x-1)+(5x+36)+6x-2)+(7x+19)+116+110=720 | | 2(x-5)=10x+9 | | 3.5=2/3t | | 5^(a+2)=1/125 | | 12+x-7=2(x-7) | | 90y=3 | | 12+x-7=(x-7) | | 3x=-82 | | x-27=8+20 | | 12+x-7=2x-14 | | 4h+3=16-15h | | 139.859.325=7.5x | | 8(x+3)+9-5=32 | | 7=3(x+2)+2 | | 7=6q+1 | | 5x-11=29.x=8 | | 9w+24=17w | | 18x-35+5x=0 | | 7^y=27 | | 12-1/x=0 | | 0.99x=208 | | .33x-3.3=-4 | | 3/4x+4=6 | | 36+6-x=2 | | -x+117=-139 | | 7b+10=52 | | 5x+6x=-4-3x | | -11+x1(-48)=25 | | 4m-5=m | | 11=p/7+3= |