Y+1=4/5(x+5)

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Solution for Y+1=4/5(x+5) equation:



+1=4/5(Y+5)
We move all terms to the left:
+1-(4/5(Y+5))=0
Domain of the equation: 5(Y+5))!=0
Y∈R
We multiply all the terms by the denominator
-(4+1*5(Y+5))=0
We calculate terms in parentheses: -(4+1*5(Y+5)), so:
4+1*5(Y+5)
determiningTheFunctionDomain 1*5(Y+5)+4
Wy multiply elements
5Y(Y+4
Back to the equation:
-(5Y(Y+4)
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
We calculate terms in parentheses: -(5Y(Y+4), so:
5Y(Y+4
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5Y(Y+4
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5Y(Y+4
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5Y(Y+4
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5Y(Y+4
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5Y(Y+4
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5Y(Y+4

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