Y+1=2/3(x+5)

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Solution for Y+1=2/3(x+5) equation: 



+1=2/3(Y+5)

We move all terms to the left:

+1-(2/3(Y+5))=0



Domain of the equation: 3(Y+5))!=0

Y∈R



We multiply all the terms by the denominator


-(2+1*3(Y+5))=0



We calculate terms in parentheses: -(2+1*3(Y+5)), so:

2+1*3(Y+5)

determiningTheFunctionDomain
1*3(Y+5)+2

Wy multiply elements

3Y(Y+2

Back to the equation:

-(3Y(Y+2)





We calculate terms in parentheses: -(3Y(Y+2), so:

3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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3Y(Y+2





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