Y+11=20x+5x2-14

Solution for Y+11=20x+5x2-14 equation:

+11=20Y+5Y^2-14

We move all terms to the left:

+11-(20Y+5Y^2-14)=0

We get rid of parentheses

-5Y^2-20Y+14+11=0

We add all the numbers together, and all the variables

-5Y^2-20Y+25=0

a = -5; b = -20; c = +25;
Δ = b2-4ac
Δ = -202-4·(-5)·25
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-30}{2*-5}=\frac{-10}{-10}
=1
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+30}{2*-5}=\frac{50}{-10}
=-5
$