Xx(x+2)=168

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Solution for Xx(x+2)=168 equation:



XX(X+2)=168
We move all terms to the left:
XX(X+2)-(168)=0
We multiply parentheses
X^2+2X-168=0
a = 1; b = 2; c = -168;
Δ = b2-4ac
Δ = 22-4·1·(-168)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-26}{2*1}=\frac{-28}{2} =-14 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+26}{2*1}=\frac{24}{2} =12 $

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