Xx(1+1/x)+17=3x(2-X)

Solution for Xx(1+1/x)+17=3x(2-X) equation:

XX(1+1/X)+17=3X(2-X)

We move all terms to the left:

XX(1+1/X)+17-(3X(2-X))=0


Domain of the equation: X)!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

XX(1/X+1)-(3X(-1X+2))+17=0

We multiply parentheses

X^2+X-(3X(-1X+2))+17=0


We calculate terms in parentheses: -(3X(-1X+2)), so:

3X(-1X+2)

We multiply parentheses

-3X^2+6X

Back to the equation:

-(-3X^2+6X)


We get rid of parentheses

X^2+3X^2-6X+X+17=0

We add all the numbers together, and all the variables

4X^2-5X+17=0

a = 4; b = -5; c = +17;
Δ = b2-4ac
Δ = -52-4·4·17
Δ = -247
Delta is less than zero, so there is no solution for the equation