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X=6/5X+13
We move all terms to the left:
X-(6/5X+13)=0
Domain of the equation: 5X+13)!=0We get rid of parentheses
X∈R
X-6/5X-13=0
We multiply all the terms by the denominator
X*5X-13*5X-6=0
Wy multiply elements
5X^2-65X-6=0
a = 5; b = -65; c = -6;
Δ = b2-4ac
Δ = -652-4·5·(-6)
Δ = 4345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-\sqrt{4345}}{2*5}=\frac{65-\sqrt{4345}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+\sqrt{4345}}{2*5}=\frac{65+\sqrt{4345}}{10} $
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