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X=5/4X-10
We move all terms to the left:
X-(5/4X-10)=0
Domain of the equation: 4X-10)!=0We get rid of parentheses
X∈R
X-5/4X+10=0
We multiply all the terms by the denominator
X*4X+10*4X-5=0
Wy multiply elements
4X^2+40X-5=0
a = 4; b = 40; c = -5;
Δ = b2-4ac
Δ = 402-4·4·(-5)
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{105}}{2*4}=\frac{-40-4\sqrt{105}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{105}}{2*4}=\frac{-40+4\sqrt{105}}{8} $
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