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X=4X-12/X-3
We move all terms to the left:
X-(4X-12/X-3)=0
Domain of the equation: X-3)!=0We get rid of parentheses
X∈R
X-4X+12/X+3=0
We multiply all the terms by the denominator
X*X-4X*X+3*X+12=0
We add all the numbers together, and all the variables
3X+X*X-4X*X+12=0
Wy multiply elements
X^2-4X^2+3X+12=0
We add all the numbers together, and all the variables
-3X^2+3X+12=0
a = -3; b = 3; c = +12;
Δ = b2-4ac
Δ = 32-4·(-3)·12
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{17}}{2*-3}=\frac{-3-3\sqrt{17}}{-6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{17}}{2*-3}=\frac{-3+3\sqrt{17}}{-6} $
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