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X=4/5X+1
We move all terms to the left:
X-(4/5X+1)=0
Domain of the equation: 5X+1)!=0We get rid of parentheses
X∈R
X-4/5X-1=0
We multiply all the terms by the denominator
X*5X-1*5X-4=0
Wy multiply elements
5X^2-5X-4=0
a = 5; b = -5; c = -4;
Δ = b2-4ac
Δ = -52-4·5·(-4)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{105}}{2*5}=\frac{5-\sqrt{105}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{105}}{2*5}=\frac{5+\sqrt{105}}{10} $
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