X=3x(x+12x+9x)

Solution for X=3x(x+12x+9x) equation:

X=3X(X+12X+9X)

We move all terms to the left:

X-(3X(X+12X+9X))=0

We add all the numbers together, and all the variables

X-(3X(+22X))=0


We calculate terms in parentheses: -(3X(+22X)), so:

3X(+22X)

We multiply parentheses

66X^2

Back to the equation:

-(66X^2)


determiningTheFunctionDomain
-66X^2+X=0

a = -66; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-66)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-66}=\frac{-2}{-132}
=1/66
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-66}=\frac{0}{-132}
=0
$