X=3/10x+4

Solution for X=3/10x+4 equation:

X=3/10X+4

We move all terms to the left:

X-(3/10X+4)=0


Domain of the equation: 10X+4)!=0

X∈R


We get rid of parentheses

X-3/10X-4=0

We multiply all the terms by the denominator


X*10X-4*10X-3=0

Wy multiply elements

10X^2-40X-3=0

a = 10; b = -40; c = -3;
Δ = b2-4ac
Δ = -402-4·10·(-3)
Δ = 1720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1720}=\sqrt{4*430}=\sqrt{4}*\sqrt{430}=2\sqrt{430}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{430}}{2*10}=\frac{40-2\sqrt{430}}{20}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{430}}{2*10}=\frac{40+2\sqrt{430}}{20}
$