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X=2X-6/3X-2
We move all terms to the left:
X-(2X-6/3X-2)=0
Domain of the equation: 3X-2)!=0We get rid of parentheses
X∈R
X-2X+6/3X+2=0
We multiply all the terms by the denominator
X*3X-2X*3X+2*3X+6=0
Wy multiply elements
3X^2-6X^2+6X+6=0
We add all the numbers together, and all the variables
-3X^2+6X+6=0
a = -3; b = 6; c = +6;
Δ = b2-4ac
Δ = 62-4·(-3)·6
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{3}}{2*-3}=\frac{-6-6\sqrt{3}}{-6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{3}}{2*-3}=\frac{-6+6\sqrt{3}}{-6} $
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