X=2x(x+10)

Solution for X=2x(x+10) equation:

X=2X(X+10)

We move all terms to the left:

X-(2X(X+10))=0


We calculate terms in parentheses: -(2X(X+10)), so:

2X(X+10)

We multiply parentheses

2X^2+20X

Back to the equation:

-(2X^2+20X)


We get rid of parentheses

-2X^2+X-20X=0

We add all the numbers together, and all the variables

-2X^2-19X=0

a = -2; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·(-2)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*-2}=\frac{0}{-4}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*-2}=\frac{38}{-4}
=-9+1/2
$