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X=2/3X-20
We move all terms to the left:
X-(2/3X-20)=0
Domain of the equation: 3X-20)!=0We get rid of parentheses
X∈R
X-2/3X+20=0
We multiply all the terms by the denominator
X*3X+20*3X-2=0
Wy multiply elements
3X^2+60X-2=0
a = 3; b = 60; c = -2;
Δ = b2-4ac
Δ = 602-4·3·(-2)
Δ = 3624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3624}=\sqrt{4*906}=\sqrt{4}*\sqrt{906}=2\sqrt{906}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{906}}{2*3}=\frac{-60-2\sqrt{906}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{906}}{2*3}=\frac{-60+2\sqrt{906}}{6} $
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