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X=(9X+5)(6X-6)
We move all terms to the left:
X-((9X+5)(6X-6))=0
We multiply parentheses ..
-((+54X^2-54X+30X-30))+X=0
We calculate terms in parentheses: -((+54X^2-54X+30X-30)), so:We add all the numbers together, and all the variables
(+54X^2-54X+30X-30)
We get rid of parentheses
54X^2-54X+30X-30
We add all the numbers together, and all the variables
54X^2-24X-30
Back to the equation:
-(54X^2-24X-30)
X-(54X^2-24X-30)=0
We get rid of parentheses
-54X^2+X+24X+30=0
We add all the numbers together, and all the variables
-54X^2+25X+30=0
a = -54; b = 25; c = +30;
Δ = b2-4ac
Δ = 252-4·(-54)·30
Δ = 7105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7105}=\sqrt{49*145}=\sqrt{49}*\sqrt{145}=7\sqrt{145}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-7\sqrt{145}}{2*-54}=\frac{-25-7\sqrt{145}}{-108} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+7\sqrt{145}}{2*-54}=\frac{-25+7\sqrt{145}}{-108} $
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