X=(2m+3)+11

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Solution for X=(2m+3)+11 equation:



X=(2X+3)+11
We move all terms to the left:
X-((2X+3)+11)=0
We calculate terms in parentheses: -((2X+3)+11), so:
(2X+3)+11
We get rid of parentheses
2X+3+11
We add all the numbers together, and all the variables
2X+14
Back to the equation:
-(2X+14)
We get rid of parentheses
X-2X-14=0
We add all the numbers together, and all the variables
-1X-14=0
We move all terms containing X to the left, all other terms to the right
-X=14
X=14/-1
X=-14

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