X2=12(y-1)

Solution for X2=12(y-1) equation:

X2=12(X-1)

We move all terms to the left:

X2-(12(X-1))=0

We add all the numbers together, and all the variables

X^2-(12(X-1))=0


We calculate terms in parentheses: -(12(X-1)), so:

12(X-1)

We multiply parentheses

12X-12

Back to the equation:

-(12X-12)


We get rid of parentheses

X^2-12X+12=0

a = 1; b = -12; c = +12;
Δ = b2-4ac
Δ = -122-4·1·12
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{6}}{2*1}=\frac{12-4\sqrt{6}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{6}}{2*1}=\frac{12+4\sqrt{6}}{2}
$