X2-92x+960=0

Solution for X2-92x+960=0 equation:

X2-92X+960=0

We add all the numbers together, and all the variables

X^2-92X+960=0

a = 1; b = -92; c = +960;
Δ = b2-4ac
Δ = -922-4·1·960
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-68}{2*1}=\frac{24}{2}
=12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+68}{2*1}=\frac{160}{2}
=80
$