X2-5x+33=7x-3

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Solution for X2-5x+33=7x-3 equation: 



X2-5X+33=7X-3

We move all terms to the left:

X2-5X+33-(7X-3)=0

We add all the numbers together, and all the variables

X^2-5X-(7X-3)+33=0

We get rid of parentheses

X^2-5X-7X+3+33=0

We add all the numbers together, and all the variables

X^2-12X+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{12}{2}=6$

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