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X2-4X=3X+88
We move all terms to the left:
X2-4X-(3X+88)=0
We add all the numbers together, and all the variables
X^2-4X-(3X+88)=0
We get rid of parentheses
X^2-4X-3X-88=0
We add all the numbers together, and all the variables
X^2-7X-88=0
a = 1; b = -7; c = -88;
Δ = b2-4ac
Δ = -72-4·1·(-88)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{401}}{2*1}=\frac{7-\sqrt{401}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{401}}{2*1}=\frac{7+\sqrt{401}}{2} $
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