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X2-47X+120=0
We add all the numbers together, and all the variables
X^2-47X+120=0
a = 1; b = -47; c = +120;
Δ = b2-4ac
Δ = -472-4·1·120
Δ = 1729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-\sqrt{1729}}{2*1}=\frac{47-\sqrt{1729}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+\sqrt{1729}}{2*1}=\frac{47+\sqrt{1729}}{2} $
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