X2-40x+32x-1280=0

Solution for X2-40x+32x-1280=0 equation:

X2-40X+32X-1280=0

We add all the numbers together, and all the variables

X^2-8X-1280=0

a = 1; b = -8; c = -1280;
Δ = b2-4ac
Δ = -82-4·1·(-1280)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-72}{2*1}=\frac{-64}{2}
=-32
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+72}{2*1}=\frac{80}{2}
=40
$