X2-3x=6x+10

Solution for X2-3x=6x+10 equation:

X2-3X=6X+10

We move all terms to the left:

X2-3X-(6X+10)=0

We add all the numbers together, and all the variables

X^2-3X-(6X+10)=0

We get rid of parentheses

X^2-3X-6X-10=0

We add all the numbers together, and all the variables

X^2-9X-10=0

a = 1; b = -9; c = -10;
Δ = b2-4ac
Δ = -92-4·1·(-10)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-11}{2*1}=\frac{-2}{2}
=-1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+11}{2*1}=\frac{20}{2}
=10
$