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X2-3X-648=0
We add all the numbers together, and all the variables
X^2-3X-648=0
a = 1; b = -3; c = -648;
Δ = b2-4ac
Δ = -32-4·1·(-648)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-51}{2*1}=\frac{-48}{2} =-24 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+51}{2*1}=\frac{54}{2} =27 $
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