X2-36x+x=0

Solution for X2-36x+x=0 equation:

X2-36X+X=0

We add all the numbers together, and all the variables

X^2-35X=0

a = 1; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·1·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*1}=\frac{0}{2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*1}=\frac{70}{2}
=35
$