X2-36x+4=0

Solution for X2-36x+4=0 equation:

X2-36X+4=0

We add all the numbers together, and all the variables

X^2-36X+4=0

a = 1; b = -36; c = +4;
Δ = b2-4ac
Δ = -362-4·1·4
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-16\sqrt{5}}{2*1}=\frac{36-16\sqrt{5}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+16\sqrt{5}}{2*1}=\frac{36+16\sqrt{5}}{2}
$