X2-28x+160=0

Solution for X2-28x+160=0 equation:

X2-28X+160=0

We add all the numbers together, and all the variables

X^2-28X+160=0

a = 1; b = -28; c = +160;
Δ = b2-4ac
Δ = -282-4·1·160
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-12}{2*1}=\frac{16}{2}
=8
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+12}{2*1}=\frac{40}{2}
=20
$