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X2-26X+153=0
We add all the numbers together, and all the variables
X^2-26X+153=0
a = 1; b = -26; c = +153;
Δ = b2-4ac
Δ = -262-4·1·153
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-8}{2*1}=\frac{18}{2} =9 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+8}{2*1}=\frac{34}{2} =17 $
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