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X2-200X+2000=0
We add all the numbers together, and all the variables
X^2-200X+2000=0
a = 1; b = -200; c = +2000;
Δ = b2-4ac
Δ = -2002-4·1·2000
Δ = 32000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32000}=\sqrt{6400*5}=\sqrt{6400}*\sqrt{5}=80\sqrt{5}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-80\sqrt{5}}{2*1}=\frac{200-80\sqrt{5}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+80\sqrt{5}}{2*1}=\frac{200+80\sqrt{5}}{2} $
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