X2-12x+36=90

Solution for X2-12x+36=90 equation:

X2-12X+36=90

We move all terms to the left:

X2-12X+36-(90)=0

We add all the numbers together, and all the variables

X^2-12X-54=0

a = 1; b = -12; c = -54;
Δ = b2-4ac
Δ = -122-4·1·(-54)
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{10}}{2*1}=\frac{12-6\sqrt{10}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{10}}{2*1}=\frac{12+6\sqrt{10}}{2}
$