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X2-100X+1200=0
We add all the numbers together, and all the variables
X^2-100X+1200=0
a = 1; b = -100; c = +1200;
Δ = b2-4ac
Δ = -1002-4·1·1200
Δ = 5200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5200}=\sqrt{400*13}=\sqrt{400}*\sqrt{13}=20\sqrt{13}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-20\sqrt{13}}{2*1}=\frac{100-20\sqrt{13}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+20\sqrt{13}}{2*1}=\frac{100+20\sqrt{13}}{2} $
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