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X2+X=650
We move all terms to the left:
X2+X-(650)=0
We add all the numbers together, and all the variables
X^2+X-650=0
a = 1; b = 1; c = -650;
Δ = b2-4ac
Δ = 12-4·1·(-650)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-51}{2*1}=\frac{-52}{2} =-26 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+51}{2*1}=\frac{50}{2} =25 $
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