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X2+X2+6X+9=225
We move all terms to the left:
X2+X2+6X+9-(225)=0
We add all the numbers together, and all the variables
2X^2+6X-216=0
a = 2; b = 6; c = -216;
Δ = b2-4ac
Δ = 62-4·2·(-216)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-42}{2*2}=\frac{-48}{4} =-12 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+42}{2*2}=\frac{36}{4} =9 $
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