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X2+5X-100=0
We add all the numbers together, and all the variables
X^2+5X-100=0
a = 1; b = 5; c = -100;
Δ = b2-4ac
Δ = 52-4·1·(-100)
Δ = 425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{425}=\sqrt{25*17}=\sqrt{25}*\sqrt{17}=5\sqrt{17}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{17}}{2*1}=\frac{-5-5\sqrt{17}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{17}}{2*1}=\frac{-5+5\sqrt{17}}{2} $
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