X2+50x+600=0

Solution for X2+50x+600=0 equation:

X2+50X+600=0

We add all the numbers together, and all the variables

X^2+50X+600=0

a = 1; b = 50; c = +600;
Δ = b2-4ac
Δ = 502-4·1·600
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10}{2*1}=\frac{-60}{2}
=-30
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10}{2*1}=\frac{-40}{2}
=-20
$