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X2+5.5X-1.5=0
We add all the numbers together, and all the variables
X^2+5.5X-1.5=0
a = 1; b = 5.5; c = -1.5;
Δ = b2-4ac
Δ = 5.52-4·1·(-1.5)
Δ = 36.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.5)-\sqrt{36.25}}{2*1}=\frac{-5.5-\sqrt{36.25}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.5)+\sqrt{36.25}}{2*1}=\frac{-5.5+\sqrt{36.25}}{2} $
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