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X2+4X-2=2X+6
We move all terms to the left:
X2+4X-2-(2X+6)=0
We add all the numbers together, and all the variables
X^2+4X-(2X+6)-2=0
We get rid of parentheses
X^2+4X-2X-6-2=0
We add all the numbers together, and all the variables
X^2+2X-8=0
a = 1; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·1·(-8)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6}{2*1}=\frac{-8}{2} =-4 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6}{2*1}=\frac{4}{2} =2 $
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