X2+40x-32000=0

Solution for X2+40x-32000=0 equation:

X2+40X-32000=0

We add all the numbers together, and all the variables

X^2+40X-32000=0

a = 1; b = 40; c = -32000;
Δ = b2-4ac
Δ = 402-4·1·(-32000)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-360}{2*1}=\frac{-400}{2}
=-200
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+360}{2*1}=\frac{320}{2}
=160
$