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X2+3X=29-X2
We move all terms to the left:
X2+3X-(29-X2)=0
We add all the numbers together, and all the variables
-(-1X^2+29)+X2+3X=0
We add all the numbers together, and all the variables
X^2-(-1X^2+29)+3X=0
We get rid of parentheses
X^2+1X^2+3X-29=0
We add all the numbers together, and all the variables
2X^2+3X-29=0
a = 2; b = 3; c = -29;
Δ = b2-4ac
Δ = 32-4·2·(-29)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{241}}{2*2}=\frac{-3-\sqrt{241}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{241}}{2*2}=\frac{-3+\sqrt{241}}{4} $
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