X2+3x2=x-4x+25

Solution for X2+3x2=x-4x+25 equation:

X2+3X^2=X-4X+25

We move all terms to the left:

X2+3X^2-(X-4X+25)=0

We add all the numbers together, and all the variables

3X^2+X2-(-3X+25)=0

We add all the numbers together, and all the variables

4X^2-(-3X+25)=0

We get rid of parentheses

4X^2+3X-25=0

a = 4; b = 3; c = -25;
Δ = b2-4ac
Δ = 32-4·4·(-25)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{409}}{2*4}=\frac{-3-\sqrt{409}}{8}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{409}}{2*4}=\frac{-3+\sqrt{409}}{8}
$