X2+2x=49

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Solution for X2+2x=49 equation:



X2+2X=49
We move all terms to the left:
X2+2X-(49)=0
We add all the numbers together, and all the variables
X^2+2X-49=0
a = 1; b = 2; c = -49;
Δ = b2-4ac
Δ = 22-4·1·(-49)
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10\sqrt{2}}{2*1}=\frac{-2-10\sqrt{2}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10\sqrt{2}}{2*1}=\frac{-2+10\sqrt{2}}{2} $

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